Math, asked by Shraddhapatil2302, 9 months ago

A metal euboid of measures 16 cm x 11 cm x 10 cm was melted
to make coins. How many coins were made, if the thickness and
diameter of each coin was 2 mm and 2 cm respectively ?
(it = 3.14)​

Answers

Answered by nehar1306
1

Answer:

The number of coins were made is 2802.

Step-by-step explanation:

Volume of metal piped = 16 cm ×11 cm × 10 cm =1760 cm^3

Now thickness of coin = 2 mm

1 mm = 0.1 cm

2 mm = 0.2 cm

thus the thickness(h) of coin is 0.2 cm

Radius of coin(r) = diameter /2 =2/2 =1 cm

Since coin is in cylindrical shape .

So, volume of coin = πr^2h

use π =3.14

= 0.628 cm^3

Thus no. of coins were made = volume of pipe/volume of 1 coin

= 1760/0.628 =2802.54

Thus  no. of coins were made is 2802

Answered by arsh122100
6

Step-by-step explanation:

Dimensions of pipe

Dimensions of coin

No of coins = T. Area of pipe / T. Area of one coin

=(0.2×2216×11×10 \times 7) \div (0.2 \times 22)

= 16×11×10×7

=2800 coins

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