Question

A metal forms metal oxide in prescence of oxygen and its weight is increased by 22 %. The equivalent weight of the metal will be

1. 22.15
2. 33.33
3. 36.36
4. 44.22

Answer 1

Correct Option is :  3

Explanation :

Metal + Oxygen ----> Metal oxide

one equivalent weight of metal reacts with one equivalent weight of oxygen to form metal oxide.

Equivalent weight of oxygen [ oxide ion] = Molar mass of O2/ charge on oxygen=16 g mol ⁻¹ / 2 mol eq⁻¹=8 g eq⁻¹

Therefore M grams of metal reacts with 8 grams of oxygen  to form metal oxide which will have 8 grams more than mass of metal M. 

This 8 grams is 22% of Mx 22/100= 8 grams

M=100x8/22 =36.36