A metal forms metal oxide in prescence of oxygen and its weight is increased by 22 %. The equivalent weight of the metal will be
1. 22.15
2. 33.33
3. 36.36
4. 44.22
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3
Correct Option is : 3
Explanation :
Metal + Oxygen ----> Metal oxide
one equivalent weight of metal reacts with one equivalent weight of oxygen to form metal oxide.
Equivalent weight of oxygen [ oxide ion] = Molar mass of O2/ charge on oxygen=16 g mol ⁻¹ / 2 mol eq⁻¹=8 g eq⁻¹
Therefore M grams of metal reacts with 8 grams of oxygen to form metal oxide which will have 8 grams more than mass of metal M.
This 8 grams is 22% of Mx 22/100= 8 grams
M=100x8/22 =36.36
Explanation :
Metal + Oxygen ----> Metal oxide
one equivalent weight of metal reacts with one equivalent weight of oxygen to form metal oxide.
Equivalent weight of oxygen [ oxide ion] = Molar mass of O2/ charge on oxygen=16 g mol ⁻¹ / 2 mol eq⁻¹=8 g eq⁻¹
Therefore M grams of metal reacts with 8 grams of oxygen to form metal oxide which will have 8 grams more than mass of metal M.
This 8 grams is 22% of Mx 22/100= 8 grams
M=100x8/22 =36.36
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