Question

A metal has a threshold wavelength of 6400å calculate threshold frequency

Answer 1

1) as we know frequency=speedog light/wavelength threshold frequency=3※10^8 / 6000※10^-10 here sign ※→ multiply ^→power threshold frequency= 5※10^14Hz 2) work function=h※threshold frequency/1.6※10^-19 work function=194.4eV

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Answer 2

The threshold frequency of the metal is $4.68\times 10^{14}\ Hz$.

Explanation:

Given that,

The threshold wavelength of the metal, $\lambda=6400\ A=6400\times 10^{-10}\ m$

To find,

Threshold frequency

Solution,

The relation between the frequency, wavelength and the speed is given by :

$v=f\times \lambda$

Here, v = c

$f=\dfrac{c}{\lambda}$

$f=\dfrac{3\times 10^8\ m/s}{6400\times 10^{-10}\ m}$

$f=4.68\times 10^{14}\ Hz$

So, the threshold frequency of the metal is $4.68\times 10^{14}\ Hz$. Hence, this is the required solution.

Learn more,

Frequency and wavelength

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