Question

A metal hemisphere of diameter 3 cm is redrawn into a wire of thickness 0.3 cm, then find the length of the
wire.​

Answer 1

Answer:-

Length =25 cm

Calculation :-

Vol. of sphere =

$= > \frac{4}{3} \times \pi \times {r}^{3}$

$= > \frac{4}{3} \times \frac{22}{7} \times 3cm {}^{3}$

$= > \pi \times 0.15$

=> 4/3 × π × 27 cm³= π × (3/20)² × L cm³

=> L = 5×5×9/9×9

=> L =25

Answer 2

Answer:

1m

Step-by-step explanation:

For hemisphere, R = 1.5 cm

For cylinder (wire), r = 0.15cm, H = ?

$V (hemisphere) = V (cylinder)$

$2/3 \pi R^3 = \pi r^2 H$

$2/3 (1.5)^3 = (0.15)^2H$

Solving, we get:

H = 1m