Question

A metal M forms an oxide having the formula M203. It is dissolved both in dilute sulphuric and dilute sodium hydroxide solution. Identify the metal& write equations for the reaction involved.

Answer 1

the metal is iron(Fe) it forms ferric oxide (Fe₂O₃) which is amphoteric that is it shows the nature of both acidic and basic.
Fe₂O₃+3H₂SO₄⇒Fe₂(SO₄)₃+3H₂O
&
Fe₂O₃+ 6NaOH⇒2Fe(OH)₃+ 3H₂O.
SUGGEST FOR EDITION.

Answer 2

A metal M forms an oxide having the formula $M_{2} O_{3}$. It is dissolved both in dilute sulphuric and dilute sodium hydroxide solution. The metal and equation in the involved reaction are.

The only metal which reacts both with acids and bases according to the formula $M_{2} O_{3}$ is aluminum. From the formula, the valency is 3 electrons.

So, its electronic configuration is 2, 8, 3. Its Atomic Number is 13.

Hence, The metal is Aluminium.

The equation:

Fe$_{2}$O$_{3}$ + 6NaOH ⇒ 2Fe(OH)$_{3}$ + 3H$_{2}$O