A metal of work function of 2.5eV is lit by a radiation of unknown frequency. Determine the maximum wavelength of incident radiation?
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Answer:
Energy of incident radiation is E=
λ
hc
=
3×10
−7
6.6×10
−34
×3×10
8
=6.6×10
−19
J.
Also, work function is ϕ=2×1.6×10
−19
J=3.2×10
−19
J.
Hence, maximum kinetic energy of emitted photo electrons will be 6.6×10
−19
J−3.2×10
−19
J=3.4×10
−19
J.
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