Chemistry, asked by Mesha8176, 9 months ago

A metal oxide has 40% oxygen. The percentage of chlorine in its chloride is

Answers

Answered by Mysha77
0

Answer:

of O atoms. Therefore, Let the molar mass of M be M. Thus, the percentage of chlorine is 71y*100/(71y+xM) = 71y*100/(71y + 24y) = 74.74%.

Maybe its helpful

Similar questions