Question

A metal oxide X is black in colour. When X is heated with hydrogen gas, metal Y is formed which is reddish brown in colour identify X and Y write the chemical reaction involved which substance is getting oxidised and which substance is getting reduced? identify oxidising and reducing agent.​

Answer 1

|| GIVEN ||

• Metal Oxide which is black in colour.
• When X is heated with Hydrogen , It produces Reddish brown gas , Which is called Y.

|| TO FIND ||

• The metals X and Y.
• Chemical reation between X and Y.
• Which is been oxidised or reduced.

|| SOLUTION ||

We can guess by the product given which happens in our everyday life. Iron gets rusts when mixed with air since water ( H20 ) makes it get rusted and produces Reddish brown colour. But Iron ( Fe ) Wont react with Hydrogen gas. So the Metal which is black in colour is Copper ( Cu ).

• X = CuO ( Cuprous Oxide )

When this cuprous Oxide gets heated up with hydrogen gas , It produces Reddish brown gas.

$CuO (s) + H2 (g) → Cu (s) + H2O(l)$

So here the Copper and Water is the Y

• Y = Cu (s) + H2O(l)

So , Hydrogen ( H2 ) is getting oxidised and CuO is getting reduced.

→ Therefore , CuO is Oxidising agent and H2 is a reducing agent.

* * * * * * * * * * * * * * * * * * * * * * * * * *

Answer 2

Answer:

Required Answer :-

So,

Element X is black and when element X is heated with hydrogen then metal Y is formed which is reddish brown in colour.

Here

Element X = Copper oxide

When copper oxide is heated with hydrogen then it becomes copper

Now

$\bf CuO + H_2 \longrightarrow Cu + H_2O$

So,

Oxidise substance = CuO

Reducing agent = H2