A metal parallelopiped of measures 16 cm*11cm*10 cm was melted to make coins. How many coins were made if the thickness and diameter of each coin was 2 mm and 2 cm respectively ?
Answers
Answer:
2800
Step-by-step explanation:
Given A metal parallelopiped of measures 16 cm*11 cm*10 cm was melted to make coins. How many coins were made if the thickness and diameter of each coin was 2 mm and 2 cm respectively
Each coin radius , r = d/2 = 2/2 = 1 cm
Given thickness of each coin h = 2 mm
10 mm = 1 cm
2 mm = 2/10 = 0.2 cm
Now let t he number of coins be C
So C = volume of metal / volume of metal in eac h coin
C = 16 x 11 x 10 / π r^2 h
C = 16 x 11 x 10 / 22/7 x 1 x 0.2
C = 2800
So the number of coins will be 2800
Answer:
2800 coins
Step-by-step explanation:
Volume of pipe = 16 * 10 * 11 cm³
Volume of coin = πR²*thickness
π = 22/7
R = Diameter /2 = 2/2 = 1 cm
Thickness = 2 mm = 2/10 cm
Volume of coin = (22/7) * (1)² * 2/10
Number of coins = Volume of pipe/Volume of one coin
=>Number of coins = (16 * 10 * 11 )/ ((22/7) * (1)² * 2/10)
= (16 * 10 * 11 * 10 * 7 )/ (22 ** 2)
= (16 * 10 * 10 * 7 )/(2 * 2)
= 4 * 10 * 10 * 7
= 2800