Question

a metal piece of mass 250 gram at 80 degree is dropped into 120 gram at 20 degrees. Find the final temperature reached if the specific heat capacity of metal is 0.09cal

Answer 1

Answer:

sorry to hear that you can

Answer 2

The final temperature of the mixture is 30°C.

Given,

A metal piece of mass 250 grams at 80°C is dropped into 120 grams of water at 20°C.

The specific heat capacity of the metal is 0.09 cal.

To Find,

The final temperature.

Solution,

Let us assume that the final temperature is x.

Now, the energy amount going out of the warm water is equal to the energy amount going into the cool water

So,

q lost = q gain

(250) (80 − x)(0.09) = (120) (x − 20.0) (1)

80-x = 120/22.5(x-20)

80-x = 5(x-20)

80-x = 5x-100

180 = 6x

x = 30°C

Hence, the final temperature of the mixture is 30°C.

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