Question

A metal pipe 63cm long has an inner diameter 6cm and outer diameter 7cm. If the metal weight 7.5g per cm^(3) find the weight of the metal pipe.

Answer 1

Answer:

the answer is c

Step-by-step explanation:

Answer 2

Answer :-

• Weight of Metal pipe = 4826.25 g OR 4.82625 Kg

Given :-

• Length of pipe (Here Height) = 63 cm
• Outer Diameter = 7 cm
• Inner Diameter = 6 cm

To Find :-

• Weight of Metal pipe = ?

Explanation :-

In order to find the find the weight to the metal pipe, First we need to Find the Inner Radius and Outer Radius

$\blue { \boxed { \bf \bigstar \: Radius = \dfrac{Diameter}{2} \: \bigstar }}$

$\rm \odot \: Outer \: Radius \: (R) = \frac{7}{2} = \bold{3.5 \: cm}$

$\rm \odot \: Inner \: Radius \: (r) = \frac{6}{2} = \bold{3 \: cm}$

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Now we need to find the Volume of Metal of pipe by Subtracting the Inner Volume and Outer Volume.

$\blue { \boxed { \bf \bigstar \: Volume \: of \: Metal \: in \: Pipe = \pi h(R^2 - r^2) \: \bigstar }}$

$\rm \hookrightarrow \pi h (R^2 - r^2) = Volume \: of \: Metal \: in \: Pipe$

$\rm \hookrightarrow \dfrac{22}{7} \times 63 \: [(3.5)^2 - (3)^2]$

$\rm \hookrightarrow 22 \times 9 \: \times (12.25 - 9)$

$\rm \hookrightarrow 22 \times 9 \: \times 3.25$

$\rm \hookrightarrow 22 \times 29.25$

$\green { \bf \hookrightarrow 643.5 \: cm^3 }$

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Now, we will find the weight of the pipe

$\rm \hookrightarrow Weight \: in \: 1 \: cm^3 = \bold{7.5 \: g}$

$\rm \hookrightarrow Weight \: in \: 643.5 \: cm^3,$

            $\rm = (643.5 \times 7.5) \: g}$

          $\red { \underline { \boxed { \bf = 4826.25 \: g \quad OR \quad 4.82625 \: Kg } }}}$

Hence, the Weight of Metal in the pipe is 4826.25 g OR 4.82625 Kg.

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                                  $\underline { \underline { \bf \huge \text More \: To \: Know }}$

Formulas Related to Cylinder

$\rm \odot \: TSA \: of \: Cylinder = 2 \pi r(r + h)$

$\rm \odot \: CSA \: of \: Cylinder = 2 \pi rh$

$\rm \odot \: Volume \: of \: Cylinder = \pi r^2 h$