Math, asked by Vishalsamant4965, 1 month ago

A metal pipe 63cm long has an inner diameter 6cm and outer diameter 7cm. If the metal weight 7.5g per cm^(3) find the weight of the metal pipe.

Answers

Answered by ciarareagan98
0

Answer:

the answer is c

Step-by-step explanation:

Answered by Agamsain
1

Answer :-

  • Weight of Metal pipe = 4826.25 g OR 4.82625 Kg

Given :-

  • Length of pipe (Here Height) = 63 cm
  • Outer Diameter = 7 cm
  • Inner Diameter = 6 cm

To Find :-

  • Weight of Metal pipe = ?

Explanation :-

In order to find the find the weight to the metal pipe, First we need to Find the Inner Radius and Outer Radius

\blue { \boxed { \bf \bigstar \: Radius = \dfrac{Diameter}{2} \: \bigstar }}

\rm \odot \: Outer \: Radius \: (R) = \frac{7}{2} = \bold{3.5 \: cm}

\rm \odot \: Inner \: Radius \: (r) = \frac{6}{2} = \bold{3 \: cm}

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Now we need to find the Volume of Metal of pipe by Subtracting the Inner Volume and Outer Volume.

\blue { \boxed { \bf \bigstar \: Volume \: of \: Metal \: in \: Pipe = \pi h(R^2 - r^2) \: \bigstar }}

\rm \hookrightarrow \pi h (R^2 - r^2) = Volume \: of \: Metal \: in \: Pipe

\rm \hookrightarrow \dfrac{22}{7} \times 63 \: [(3.5)^2 - (3)^2]

\rm \hookrightarrow 22 \times 9 \: \times (12.25 - 9)

\rm \hookrightarrow 22 \times 9 \: \times 3.25

\rm \hookrightarrow 22 \times 29.25

\green { \bf \hookrightarrow 643.5 \: cm^3 }

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Now, we will find the weight of the pipe

\rm \hookrightarrow Weight \: in \: 1 \: cm^3 = \bold{7.5 \: g}

\rm \hookrightarrow Weight \: in \: 643.5 \: cm^3,

            \rm = (643.5 \times 7.5) \: g}

          \red { \underline { \boxed { \bf = 4826.25 \: g \quad OR \quad 4.82625 \: Kg } }}}

Hence, the Weight of Metal in the pipe is 4826.25 g OR 4.82625 Kg.

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                                  \underline { \underline { \bf \huge \text More \: To \: Know }}

Formulas Related to Cylinder

\rm \odot \: TSA \: of \: Cylinder = 2 \pi r(r + h)

\rm \odot \: CSA \: of \: Cylinder = 2 \pi rh

\rm \odot \: Volume \: of \: Cylinder = \pi r^2 h

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