Math, asked by ephraimgopi1976, 7 months ago

Sin 5A -Sin 3A divided by
Cos5a + 2cos4A +COS3A

Answers

Answered by shenoinandana2019

1

Answer:

sinA÷(cosA+1)

Step-by-step explanation:

sin5A-sin3A=2cos4AsinA

cos5A+2cos4A+cos3A=2cos4AcosA+2cos4A

2cos4AsinA/2cos4AcosA+2cos4A

taking 2 cos4A common from the denominator

2cos4AsinA/2cos4A(cosA+1)

cancelling 2cos4A from numerator and denominator,we get

sinA/(cosA+1)

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