A metal pipe is 7 m long, the cross-section has an inner diameter of 2m and outer diameter of 2.2m.find the cost of painting the pipe from both sides at a rate of ¢10 per sq m (pie =22/7)
Answers
Answered by
107
Given h = 7m.
Given Inner diameter = 2m. Then, Radius of inner diameter r = 1m.
Given Outer diameter = 2.2m. Then, Radius of outer diameter R = 1.1m.
We know that Inner curved surface area = 2pirh
= 2 * 22/7 * 7
= 44.
We know that Outer curved surface area = 2 * (22/7) * (1.1) * 7
= 48.4
Now,
Total surface area = 2piRh + 2pirh + 2pi(R^2 - r^2)
= 48.4 + 44 + 2 * (22/7)((1.1)^2 - (1)^2)
= 48.4 + 44 + (44/7)(0.21)
= 93.72m^2.
Then the cost of painting of pipe = 93.72 * 10
= 937.2.
Hope this helps!
Given Inner diameter = 2m. Then, Radius of inner diameter r = 1m.
Given Outer diameter = 2.2m. Then, Radius of outer diameter R = 1.1m.
We know that Inner curved surface area = 2pirh
= 2 * 22/7 * 7
= 44.
We know that Outer curved surface area = 2 * (22/7) * (1.1) * 7
= 48.4
Now,
Total surface area = 2piRh + 2pirh + 2pi(R^2 - r^2)
= 48.4 + 44 + 2 * (22/7)((1.1)^2 - (1)^2)
= 48.4 + 44 + (44/7)(0.21)
= 93.72m^2.
Then the cost of painting of pipe = 93.72 * 10
= 937.2.
Hope this helps!
Answered by
5
Answer:
937.8
Step-by-step explanation:
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