a metal pipe is 77 cm long, the inner diameter of the cross- section is 4 cm and the outer diameter is 4.4cm. find the 1. inner curved surface area2. outer curved surface area3. total surface are a
Answers
Answered by
5
here is ur ans
height of pipe = 77 cm
inner diameter = 4 cm
inner radius ( r ) = 4 / 2 = 2 cm
inner CSA =2 pii r h
2 (22 / 7 ) ( 2) (77)
=
height of pipe = 77 cm
inner diameter = 4 cm
inner radius ( r ) = 4 / 2 = 2 cm
inner CSA =2 pii r h
2 (22 / 7 ) ( 2) (77)
=
Answered by
7
Answer :-
Let
Inner radius = r
Outer radius =R
Formula for CSA of a cylinder = 2πrh
= 2×22/7×2×77
= 2×22×2×11
= 242×2×2
= 484×2
= 968 cm^2 = inner CSA
Outer CSA = 2πRh
= 2×22/7×2.4×77
= 2×11×2.4×22
= 242×4.8
= 1161.6 cm^2
TSA = (outer CSA + inner CSA) +
{2π (R^2 - r^2)}
= (968+1161.6) +{2×22/7(5.76-4)
= 2129.6 + {44/7×1.76}
= 2129.6 + (6.28×1.76)
= 2129.6 + 11.07
= 2140.66
Similar questions