Question

A metal plate 1.25 m 1.25 m 6 mm thick and weighting 90 n is placed midway in the 24 mm gap between the two vertical plane surfaces. The gap is filled with an oil of specific gravity 0.85 and dynamic viscosity 3.0n.S/m2. Determine the

Answer 1

Answer:

im getting 168.125 n

Explanation:

since plate placed midway 24 mm gap and plate thickness is 6mm so the is reduced to 18mm by newton's law of viscosity shear stress comes as 25 n/m^2 and shear force=shear stress*both side area of plate(shear force acting  both side) we get 78.125 now we want to lift the plate at const vel 0.15 m/s so the total force reuired    =90+78.125(res forec upward)=168.125N(we add weight of plate 90 becoz we are lifting the plate so We need force against 90N  upward

Answer 2

Answer:

168.08

Explanation:

thrust = vol of the liq displaced * density of liq* gravity