Question

.
A metal plate of surface
area 0.01m^2 is placed on a layer
of benzene of thickness o.1 mm. In order to move the plate
horizontally with velocity of 1m/s. the force applied is 0.06N.
Then coefficient of viscosity of benzene is
1) 0.6 Nsm^-2
2) 0.60x10^-2Nsm^-2
3) 0.60 x 10^-3Nsm^-2
4 None​

Answer 1

Answer:

don't know but apply strokes law

Explanation:

Answer 2

Answer: 3)0.60 x 10$^{-3}Nsm^{-2}$

Explanation:

The force(F) acting on the top surface is found to be directly proportional to the speed(u) and the area of each plate(A), and inversely proportional to their separation(y) as follows:

$F=\mu A{\frac {u}{y}}$

Thus, the value of the coefficient of viscosity will be

$\mu = \frac{Fy}{Au}$

Given in the question:

A = 0.01$m^2$, u = 1m/s, F = 0.06 N, and y = 0.1 mm = 0.0001m

$\mu = \frac{0.06\times0.0001}{0.01\times1}$

$\mu = 6\times 10^{-4}$