Question

A metal rod of uniform
thickness and of length 1m
is suspended at its 25 cm
division with help of a string.
The rod remains horizontally
straight when a block of
mass 2kg is suspended to
the rod at its 10cm division.
The mass of rod is:​

Answer 1

Answer:

Torques balance each other

⇒mg(25)=2g(15)

15cm is a distance of the suspended mass from point of suspension

⇒25m=30

m= 25/30

=1.2kg