Question

A metal rod of young modulus 2into10kipower12(2*10*12) pascal undergoes an elastic strain of 0.06% the energy stored per unit volume in Jm-3

Answer 1

Answer:

3600

Energy per unit volume

=1/2×Stress×Strain

=1/2×(Strain×Y)×Strain

= 1/2×Y×(Strain)²

Thus, we get, 0.5×2×10¹0×(0.0006)

. =3600

.

.

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