a metal rod of Young's modulus 2×10^10 under goes elastic strain 0.02% the energy pre unit volume stored in rod in joule/m^
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50
Young's Modulus = Y = stress/strain = σ / ε
Given Y = 2 * 10¹⁰ Pa
strain = ε = 0.02 % = 0.0002 = 2 * 10⁻⁴
Energy per unit volume = U = 1/2 * stress * strain²
U = 1/2 * σ * ε²
= 1/2 * Y ε * ε²
= 1/2 * 2 * 10¹⁰ * (2 * 10⁻⁴)³ J/m³
= 8 * 10⁻² J/m³
Given Y = 2 * 10¹⁰ Pa
strain = ε = 0.02 % = 0.0002 = 2 * 10⁻⁴
Energy per unit volume = U = 1/2 * stress * strain²
U = 1/2 * σ * ε²
= 1/2 * Y ε * ε²
= 1/2 * 2 * 10¹⁰ * (2 * 10⁻⁴)³ J/m³
= 8 * 10⁻² J/m³
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Answered by
8
Answer:
Young's modulus = stress/strain
given , Y= 2*10^10 Pa
strain = 0.02% = 0.0002= 2*10^-4
energy per unit volume = U= 1/2*stress*strain^2
U=1/2*2*10^10*(2*10^-4)^3 J/m^3
U = 8*10^-2 J/m^3
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