Question

A metal sheet having size of0.6x0.5 metre square is heated from 293 K to 520C then the final area of the hot sheet is

Answer 1

Answer:

In this case, β=2α=4X10−5

A1​ = 0.6×0.5 =  0.30 sqmt

293∘K = 20∘ C

So, t2​−t1​=dt=520−20=500

Putting all the values in

A2​=A1​(1+βdt)

A2​=0.30(1+4X10−5(500))

We get A2​=0.306 sqmt