Question

.A metal wire has a resistance of 60 Ω. It is cut into three equal lengths. Find the equivalent resistance when two parts are connected in parallel and the third part is in series with them.

Answer 1

1/20+ 1/20 + 1/20 = 3 / 20

Answer 2

Resistance of wire =60 ohm

3 parts are made so diagram would be








I________/\/\/\60/\/________I
---------/\/60\/\-------I________/\//\\/60\_________|



So Rn=Rs+Rp



1/Rp=1/60+1/60

2/60. =>. 1/30

So, Rp=30


So Rn = 60+30

So,

Rn which is net resistance would become 90ohms
If you like my answer marks it as brainlist