Physics, asked by ska150502, 8 months ago

A metal wire of linear mass density of 9.8 g/m is stretched with a tension of 10kgwt between two rigid support 1 m apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of the alternating source is

Answers

Answered by pukultanvi4444
1

Question:-A metal wire of linear mass density of 9.8 gm is stretched with a tension of 10kg-wt between two rigid supports 1 meter apart. The wire passes at its middle point between the poles of a per magnet and it vibrates in resonance when carrying an alternate current of frequency n. The frequency n of the alternating source is:

Answer:

100Hz

Explanation:

Here,λ=1m

V=

μ

T

=

9.8×10

−3

10×9.8

=100m/s

∴ frequency (n)=V/λ=100Hz

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