a metalic sphere of radius is 4.2 cm is melted and recast into the shapeof a cylinder of radius 6cm .find the height of the cylinder
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If a solid is recasted in any other solid the volume remains the same.
so,vol.of sphere=vol. of cylinder
•4/3πr cube= 2πr square ×h 4/3×22/7×42/10×42/10×42/10 = 2×22/7×6×6×h
h= 98.784/36
H=2.744
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so,vol.of sphere=vol. of cylinder
•4/3πr cube= 2πr square ×h 4/3×22/7×42/10×42/10×42/10 = 2×22/7×6×6×h
h= 98.784/36
H=2.744
plz don't forget to mark as brainliest.
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Here is ur answer ..
A metallic sphere is melted and recast into a cylinder. Then volumes are equal...
Volume of sphere =Volume of cylinder
4/3πr^3=πr^2h
π eliminated from both side
4/3×4.2×4.2×4.2=6×6×h
h=4×4.2×4.2×4.2/3×6×6
h=4×.7×.7×1.4
h=2.744cm
So the height of the cylinder is 2.7cm
HOPE IT HELPS UHH..✌️✌️✌️✌️
A metallic sphere is melted and recast into a cylinder. Then volumes are equal...
Volume of sphere =Volume of cylinder
4/3πr^3=πr^2h
π eliminated from both side
4/3×4.2×4.2×4.2=6×6×h
h=4×4.2×4.2×4.2/3×6×6
h=4×.7×.7×1.4
h=2.744cm
So the height of the cylinder is 2.7cm
HOPE IT HELPS UHH..✌️✌️✌️✌️
vishal951431:
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