The sum of a fraction and 7 times its reciprocal is 11/2. What is the fraction?
Answers
Answered by
5
Hi Friend !!!
Here is ur answer !!!!
let the fraction be x
it's reciprocal = 1/x
x+7(1/x) = 11/2
2(x²+7 )= 11x
2x² + 14 = 11x
2x²-11x + 14 = 0
2x²-4x-7x+14 = 0
2x(x-2) - 7(x-2) = 0
(2x-7)(x-2) = 0
x = 2 and 7/2
So the required fraction is 7/2
Hope it helps u : )
Here is ur answer !!!!
let the fraction be x
it's reciprocal = 1/x
x+7(1/x) = 11/2
2(x²+7 )= 11x
2x² + 14 = 11x
2x²-11x + 14 = 0
2x²-4x-7x+14 = 0
2x(x-2) - 7(x-2) = 0
(2x-7)(x-2) = 0
x = 2 and 7/2
So the required fraction is 7/2
Hope it helps u : )
Answered by
1
Let the fraction be x,
x + 7(1/x) = 11/2
x + 7/x = 11/2
2(x² + 7) = 11x
2x² + 14 - 11x = 0
2x² - 11x + 14 = 0
2x² - (7 + 4)x + 14 = 0
2x² -7x - 4x + 14 =0
x(2x - 7) - 2(2x - 7) = 0
(2x - 7)(x - 2) = 0
2x - 7 = 0 or x - 2 = 0
x = 7/2 or x= 2
Given that x is a fraction, so, x = 7/2
Required fraction is 7/2
I hope this will help you
(-:
x + 7(1/x) = 11/2
x + 7/x = 11/2
2(x² + 7) = 11x
2x² + 14 - 11x = 0
2x² - 11x + 14 = 0
2x² - (7 + 4)x + 14 = 0
2x² -7x - 4x + 14 =0
x(2x - 7) - 2(2x - 7) = 0
(2x - 7)(x - 2) = 0
2x - 7 = 0 or x - 2 = 0
x = 7/2 or x= 2
Given that x is a fraction, so, x = 7/2
Required fraction is 7/2
I hope this will help you
(-:
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