Question

A metallic ball is heated to a temperature 70 degree Celsius is dropped in a hot water at 50 degree Celsius. Heat​

Answer 1

Answer:

20%

Explanation:

0.1×400×(500−T)=0.5×4200×(T−30)+800(T−30)

⇒40(500−T)=(T−30)(2100+800)

⇒20000−40T=2900T−30×2900

⇒20000+30×2900=T(2940)

T=30.4  

o

C

T

ΔT

​  

×100=  

30

6.4

​  

×100

=20%.