Question

A metallic cylinder has radius 3cm and height 5cm .To reduce its weight,a conical hole is drilled in the cylinder.The conical hole has a radius of 3/2 cm and its depth is 8/9cm .Calculate the ratio of the volume of metal left in the cylinder to the volume of metal taken out in conical shave.

Answer 1

(1)

volume of cylinder = πr²h

                                = (22/7) * 3² * 5

                                = (22/7) * 45

                                = 990/7 cm³

(ii)

Volume of Conical hole = 1/3 πr²h

                                       = 1/3 * (22/7) * (3/2)² * (8/9)

                                       = (44/21) cm³

Metal left in the cylinder:

= (990/7) - (44/21)

= 418/3 cm³

Now,

Ratio of volume of metal lift : volume of metal taken out =

(418/3) * (21/44)

= 133/2

= 133 : 2

Hope this helps!

Answer 2

Answer:

your answer is in the picture.......

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