Question

A metallic right circular cone of 20 cm height and whose vertical angle is 60° is cut into two parts at the middle of its height by a plane parallel to its base. If the frustum so obtained be drawn into a wire of diameter 1/16 cm, find the length of the wire.
{ANSWER WITH EXPLANATION}

{ALIGARH MUSLIM UNIVERSITY BOARD OF SECONDARY AND SENIOR SECONDARY EDUCATION, SAMPLE PAPER}

Answer 1

the answer will be 7964.44

Answer 2

HELLO DEAR,




after pic solution


Let the length of wire =l.

Volume of wire = Area of cross-section × Length

= (πr2) (l)

$\pi( { \frac{1}{32} )}^{2} l$


Now,

Volume of frustum = Volume of wire

$\frac{22000}{9} = \pi( { \frac{1}{32} )}^{2} l \\ = > \frac{22000}{9} = \frac{22}{7} \times ( { \frac{1}{32}) }^{2} l \\ = > l = \frac{22000 \times 7 \times {(32)}^{2} }{7 \times 9} \\ = > l = \frac{7000 \times 1024}{9} \\ = > l = 796444.44c {m}^{2}$

I HOPE ITS HELP YOU DEAR,
THANKS