Question

A metallic slab whose weight is 50 Newton has
length of 50 cm, breadth of 40cm and width of
10 cm What would be the pressure exerted by it
When it is kept on its different faces??​

Answer 1

Given,

A metal slab whose weight , F = 50 N has length l, = 50cm , breadth, b = 40cm and width, h = 10cm.

To find,

The pressure exerted by metal slab when it is kept on its different faces.

we know a cuboid has six faces.

two l × b , two b × h and two h × l.

case 1 : for faces of l and b.

area of face, A = l × b = 50 × 40 = 2000 × 10^-6 m² = 2 × 10¯³ m²

now pressure = force/area = 50/2 × 10¯³ = 25000 N

case 2 : for faces of b and h.

area of face, A = b × h = 40 × 10 = 400 × 10^-6 m² = 4 × 10¯⁴ m²

now pressure = force/area = 50/4 × 10¯⁴ = 125000 N

case 3 : for faces of h and l.

area of face, A = h × l = 10 × 50 = 500 × 10^-6 m² = 5 × 10¯⁴ m²

now pressure = force/area = 50/5 × 10¯⁴ = 100000 N