Question

A metallic sphere a of radius a carries a charge q. It is brought in contact with an uncharged sphere bb of radius
b. The charge on sphere a now will be

Answer 1

Answer:

answer of this is a charge

Answer 2

Concept:

Charge will flow till the time the potential of the different bodies become same.

Given:

Radius of Sphere A is a

Charge on Sphere A is q

Radius of Sphere B is b

Find:

Charge on sphere 1 left

Solution:

Let q1 charge flown from sphere A to sphere B

The charge will flow till the time the potential of both spheres become same.

Potential of Sphere A = K (q-q1) / a

Potential of Sphere B = K q1 / b

Potential of Sphere A = Potential of sphere B

K (q-q1) / a = K q1 / b

(q-q1) / a = q1 / b

(q-q1) / q1 = a / b

(q-q1) / q1 = a / b

q/q1 - 1 = a/b

q/q1 = a/b +1

q1 = q/((a/b) + 1)

charge flown to Sphere B (q1) is q/((a/b) + 1)

charge left on Sphere A will be = q - q1

charge left on Sphere A will be = q - q/((a/b) + 1)

Hence charge left on Sphere A is q - q/((a/b) + 1).

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