A metallic sphere of radius 15 cm is melted and a wire of diameter 1 cm is drawn from it. Find the length of the wire.
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Answered by
12
Dear student,
Answer: length of wire would be 17992.76 cm.
Solution:
Given that Radius of sphere 15 cm.
Volume of sphere =![\frac{4}{3}( pi) (r^{3} ) \frac{4}{3}( pi) (r^{3} )](https://tex.z-dn.net/?f=+%5Cfrac%7B4%7D%7B3%7D%28+pi%29+%28r%5E%7B3%7D+%29)
=![\frac{4}{3} (3.141) ((15)^{3}) \frac{4}{3} (3.141) ((15)^{3})](https://tex.z-dn.net/?f=+%5Cfrac%7B4%7D%7B3%7D+%283.141%29+%28%2815%29%5E%7B3%7D%29+)
= 14137.17 cm³
Radius of wire = 1/2 = 0.5 cm
Wire is considered to be cylinder = π r² h
π r² h = 14137.17
h = 14137.17/π r²
h = (14137.17× 7) /(22 ×0.5²)
h = 17992.76 cm
length of wire is 17992.76 cm.
Hope it helps you.
Answer: length of wire would be 17992.76 cm.
Solution:
Given that Radius of sphere 15 cm.
Volume of sphere =
=
= 14137.17 cm³
Radius of wire = 1/2 = 0.5 cm
Wire is considered to be cylinder = π r² h
π r² h = 14137.17
h = 14137.17/π r²
h = (14137.17× 7) /(22 ×0.5²)
h = 17992.76 cm
length of wire is 17992.76 cm.
Hope it helps you.
Answered by
0
Answer:
h=18,000cm
Step-by-step explanation:
Please refer to the above attachment.
Attachments:
![](https://hi-static.z-dn.net/files/d95/c599f25ad0dac54ad738ed6fd86f28d8.jpg)
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