a metallic sphere of radius 2cm is completely immersed in water .find the force of buoyancy in it
Answers
Answered by
53
The force of buoyancy is written as
F = ρgV
where ρ is the density of the fluid, g is the acceleration due to gravity and V is the volume of the sphere.
Here g = 10 m/s2
V = (4/3)πr3 and r = 2 cm = 0.02 m
so, V = 1.67 m3
and density ρ (for water) = 997 kg/m3
so, the buoyant force can simply be calculated by substituting the above values.
thus,
buoyant force, F = 16649.9 N
F = ρgV
where ρ is the density of the fluid, g is the acceleration due to gravity and V is the volume of the sphere.
Here g = 10 m/s2
V = (4/3)πr3 and r = 2 cm = 0.02 m
so, V = 1.67 m3
and density ρ (for water) = 997 kg/m3
so, the buoyant force can simply be calculated by substituting the above values.
thus,
buoyant force, F = 16649.9 N
mayankghatpande:
i am refering hc verma in this the answer for this question is 0.328N but i am not able to solve the problem
Answered by
9
Answer:
Explanation:
Volume of sphere = 4/3 X π X r³
= 4/3 X 22/7 X (2)³
= 4/3 X 22/7 X 8
Density of water = m/v
1 g/cm³ = m/704/21 cm³
m = 704/21 g = 33.523 g = 0.03352 kg
Bouyant force = weight of liquid displaced by that object
W = mg
= 0.03352 X 9.8
= 0.3285N
Therefore Bouyant force = 0.328
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