a metallic sphere of radius 3 cm is melted and and reshape into three spheres the radius of one of these spheres is 0.75 cm and that of another is 1.25 cm find radius of the third sphere
Answers
Answered by
2
since mass of bigger sphere is distributed among the three spheres.
Therefore the total volume of metal used in big sphere equals sum of volume of metal in the three spheres .
so volume of bigger sphere = 4/3*pi*(3)³
similarly volume of 1 sphere = 4/3*pi*(0.75)³
volume of 2nd sphere = 4/3*pi*(1.25)³
volume of third = 4/3*pi*r³
where r is the radius.
Now total Volume of bigger sphere = sum of volume of each spheres
thus 3³=0.75³ + 1.25³ + r³
solve for r
>27-0.422-1.95= r³
r³=24.625
r= 2.91 cm answer
Therefore the total volume of metal used in big sphere equals sum of volume of metal in the three spheres .
so volume of bigger sphere = 4/3*pi*(3)³
similarly volume of 1 sphere = 4/3*pi*(0.75)³
volume of 2nd sphere = 4/3*pi*(1.25)³
volume of third = 4/3*pi*r³
where r is the radius.
Now total Volume of bigger sphere = sum of volume of each spheres
thus 3³=0.75³ + 1.25³ + r³
solve for r
>27-0.422-1.95= r³
r³=24.625
r= 2.91 cm answer
Similar questions