Question

A metallic wire of resistance R is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. What will be the effective resistance of the combination?​

Answer 1

Answer:

R

Explanation:

Each resistance = R/10

In series, R1 = R/10 + R/10 = 2R/10

= R/5

In parallel:

• R=R/10 + 2*[(R*R/100)/2R/10]
• = R/10 + R/10
• = R/5

• R = R1 + R2
• = R/5 + R/5
• = R