Question

A meteor is falling.How much gravitational acceleration would it experience when its height from the surface of the earth is equal to three times the radius of the earth? (Given that the acceleration due to gravity on the surface of the earth is g) (a) g/16 (b) g/14 (c) g/10 (d) g/15​

Answer 1

Answer:

Let M, R be the mass and radius of the earth. Then

g=GM/R

2

or GM=gR

2

(i)

Potential energy of the object on the surface of earth

U

1

=

R

−GMm

The potential energy of the object at a height equal to radius of the earth is

U

2

=

2R

−GMm

Gain in PE is

U

2

−U

1

=−

2R

GMm

+

R

GMm

=

2R

GMm

(

=

2R

(gR

2

)m

=

2

1

mgR.

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