Question

A meterlloc sphere of radius 4.2cm is melted and recast into the shape of a cylinder of radius 6cm. Find the height of the cylinder​

Answer 1

If the solid is recasted in any other solid the volume remains the same.

So,

Volume of sphere = Volume of cylinder

•4/3πr cube= 2πr square ×h

4/3×22/7×42/10×42/10×42/10 =

2×22/7×6×6×h

h= 98.784/36

H=2.744

$<marquee>broken$

Answer 2

Answer:

Let the height of the cylinder be h cm

Then,

Volume of the cylinder =volume of sphere

$\pi \times {6}^{2} \times h = \frac{4}{3} \times \pi \times {4.2}^{3} \\ h = \frac{4 \times 4.2 \times 4.2 \times 4.2}{3 \times 6 \times 6} \\ h = 4 \times 0.7 \times 0.7 \times 1.4$

h=2.74

the height of the cylinder is 2.74 cm