Question

. A micrometer screw has pitch of 0.5 mm and the themble has 100 equal divisions marked on it, the least count of the instrument in mm is
A. 0.05 B. 0.5 C. 0.025 D. 0.005

Answer 1

least count = pitch measurement / total no
of division

therefore, LC = 0.5/ 100
= 0.005

hope this helps you:)

Answer 2

According to the question;

Pitch = 0.5 mm

No. of division on circular scale = 100

least count =?

$least count = \frac{Pitch of the screw of the gauge}{No. of division on circular scale }$

$least count = \frac{0.5}{100} \\least count = 0.005 mm$

A micrometre screw has a pitch of 0.5 mm, and the thimble has 100 equal divisions. The least count of the instrument is 0.005 mm.

D. 0.005

• Micrometre screw gauge:- It is a tool for measuring the diameter of thin wires and the thickness of small glass or plastic sheets.
• Least count:- The screw gauge's least count is the distance moved by the tip of the screw when it is turned through one division of the head scale.

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