Question

A military camp has provisions for 630 men to last for 25 days .how many men must be transferred to another camp so that the food lasts for another 30 days
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Answer 1

Answer:

Let number of persons shifted be x.

number of persons left = 630 - x

$\frac{number \: ofpersons}{number \: ofdays} \frac{630}{25} \frac{630 - x}{30} \\ since \:less \: persons \: more \: days \\ therefore \: its \: indirect \: variation \\ therefore \: 630 \times 25 = (630 - x) \times 30 \\ 630 - x = 525 \\ x \: = 105$