Evaluate Yourself
5) A Compound on analysis gave the
following percentage composition
C=54.55%, H=9.09%, O=36.36%.
Determine the empirical formula of the
compound.
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Answer:
A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55. Its VD is 44. ... Empirical formula =C2H4O.
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