A military tent height 8.25 is in the form of a right circular cylinder of base diameter 30 m and hight 5.5 m surmounted by a right circular cone of same base radius .find the length of the canvas use in making of the tent if the breadth is 1.5 m.
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HEIGHT OF TENT = 8.25CM
HEIGHT OF CYLINDRICAL PART OF TENT = 5.5CM
DIAMETER = 30M
RADIUS = D/2 = 30/2 = 15CM
HEIGHT OF CONICAL PART OF TENT = HEIGHT OF TENT- HEIGHT OF CYLINDRICAL PART OF TENT.
= 8.25-5.5 = 3CM.
CANVAS REQUIRE TO MAKING A TENT = CSA OF CYLINDRICAL PART OF TENT+ CSA OF CONICAL PART OF TENT = 2πRH+ πRL.
SOLVE THIS AND FIND THE AREA OF CANVAS REQUIRED FOR MAKING A TENT.
AFTER FINDING THE AREA OF CANVAS.
AREA = LENGTH/ BREADTH.
PUT VALUE AND SOLVE U WILL GET THE LENGTH OF CANVAS..
HEIGHT OF CYLINDRICAL PART OF TENT = 5.5CM
DIAMETER = 30M
RADIUS = D/2 = 30/2 = 15CM
HEIGHT OF CONICAL PART OF TENT = HEIGHT OF TENT- HEIGHT OF CYLINDRICAL PART OF TENT.
= 8.25-5.5 = 3CM.
CANVAS REQUIRE TO MAKING A TENT = CSA OF CYLINDRICAL PART OF TENT+ CSA OF CONICAL PART OF TENT = 2πRH+ πRL.
SOLVE THIS AND FIND THE AREA OF CANVAS REQUIRED FOR MAKING A TENT.
AFTER FINDING THE AREA OF CANVAS.
AREA = LENGTH/ BREADTH.
PUT VALUE AND SOLVE U WILL GET THE LENGTH OF CANVAS..
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