Question

A milk container is 5/8 full. Milk is poured in at a rate of 5 liters per minute. After 14 minutes the container is 4/5 full.

Calculate the number of liters of milk which the container can hold.

PLEASE ANSWER ASAP!

Answer 1

Answer: the capacity of the container is 400 litres

Step-by-step explanation:

Let the total capacity be “x”

Amount already present = 5x/8

If milk is poured @ 5 litres per minute, in 14 minutes, there will be 14*5 litres poured

=> 70 litres poured

The container is now 4/5 full

=> 4x/5 = 70 + 5x/8

=> 70 = 4x/5 - 5x/8 = [(32-25)x] / 40 = 7X/40

=> x = (70 * 40) / 7 = 400

Therefore, the capacity of the container is 400 litres

Please brainlist my answer, if helpful!

Answer 2

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge\mathcal{\bf{{\underline{\underline{\huge\mathcal{...Answer...}}}}}}$

$\underline{\large\mathcal\red{solution}}$

A milk container is 5/8 full.

therefore...the remaining portion is=1-5/8=(3/8)

now ..milk is poured 5 lit/min for 14 minutes

therefore=(5×14)litres =70 litres milk has been poured .....and now the container is 4/5 full ...

i.e., 70 litres milk filled only

$= \frac{4}{5} - \frac{5}{8} \\ = \frac{32 - 25}{40} \\ = \frac{7}{40} \: \: portion \: of \: the \: container$

now ...(17/30) portion of the container can be filled by 70 litres of milk ...

therefore to fill the container fully

$= \frac{70}{ \frac{7}{40} } \\ = \frac{70 \times 40}{7} \: litre\: of\:milk\: is\: required\\ = 400 \: litre$

so the container can hold 400 litre of milk......

$\underline{\large\mathcal\red{hope\: this \: helps \:you......}}$