A milk container is made up of metal sheet in the shape of frustum of a cone whose volume
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Solution:Volume of a frustum cone=volume of milk container.1/3πh(R²+r²+Rr)=10459.428571/3×22/7×h((20²)+8²+20×8)=10459.428571/3×22/7×h(400+64+160)=10459.428571/3×22/7×h×624=10459.42857h=10459.42857×21/22×624=16cmh=16cmSlant height(l)=√h²(R-r)²=√16²(20-8)²√256+144=√400=20cmSlant height(l)=20cmCost of a metal sheet used in a container @ 1.40 per cm²=3218.285714×1.40=Rs.4505.6
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