Question

A milk container of height 16 cm is made of metal sheet in the form of frustum of cone with radii of its lower and upper ends as 8 cm and 20cm respectively. Find the cost of milk at the rate of rupees 22 per litre which the container can hold

Answer 1

Answer:

Given  

Height of milk container (h) = 16cm,

Radius of  lower finish of milk container (r) = 8 cm

Radius of higher finish of milk container (R) = 20 cm

volume of the milk container

mode of metal sheet within the variety of a  frustum of a cone

=> $\pi$h /3 (R$^{2}$+r$^{2}$+Rr)

=> 22/7 ×16/3 [(20)$^{2}$ +(8)$^{2}$+20×8]

=> 22×16/21 × (400+64+160)

=> 22×16×624 /21

=> 219648/21

[∵1L=1000cm$^{3}$]  

=> 10459.42$^{3}$

=> 1045942 liter

volume of the milk container is 10459.42$^{3}$

∵cost of 1 liter milk =22Rs

∴ cost of 10459.42 liter milk = 22×10459.42

=> 230.12 Rs

The required cost of milk = 230.12 Rs

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@GauravSaxena01

Answer 2

my self dinesh .

Answer:

Given that,height of milk container (h) = 16 cm,

Radius of lower end of milk container (r) = 8 cm

and radius of upper end of milk container (R) = 20 cm

Step-by-step explanation: