if tan A =5/6 ,tanB = 1/11 then prove that A+B = π/4
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tan(A+B) = tan A + tan B / 1- tanA * tanB
tan(A+B) = 5/6 + 1/11/ 1- 5/6*1/11
tan(A+B) = 1
tan(A+B) = tan π/4
A+B = π/4
tan(A+B) = 5/6 + 1/11/ 1- 5/6*1/11
tan(A+B) = 1
tan(A+B) = tan π/4
A+B = π/4
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solution is in this given attachment
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