A milk man has a mixture of milk in which ratio of milk and water is 7:4 .He sells 55 litres of milk and then he adds up 20 litres of pure water .Now ,the ratio of milk and water is 7:6 .what is new quantity of mixture?
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Answer:
ans 130L
Step-by-step explanation:
By the given condition 55 litre taken out from 7:4 milk-water mixtre
then
7x+4x=55
11x=55
x=5
Then actually 35 L of milk and 20 L of water are taken out and 20L water added to the new mixture.. now
[7x-35 (quantity of water removed)] 7
--------------------------------------------------- = ------
[4x-20 (water removed)+20(water added)] 6
by solving the eqation we get x=15
now substitute x in the equaion
7(15)-35 70 (new quantity of milk)
----------- ------->>>>> ----
4(15)-20+20 60 (new quantity of water)
Now the quantity of new mixture is 70+60=130
So new quantity of the mixture is 130 L
Such a challenging question
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