Question

. A milk vendor has 24 litres of cow milk, 42 litres of toned milk and 63 litres of double toned milk. If he wants to pack them in cans so that each can contains same litres of milk and does not want to mix any two kinds of milk in a can, then the least number of cans required is??

foĺlow kro ✌❤​

Answer 1

Answer:

Step-by-step explanation:

Given,

Quantity of cow milk = 24 litres

Quantity of toned milk = 42 litres

Quantity of double toned milk = 63 litres

To Find,

The least number of cans required.

Solution,

For the maximum number, we take the HCF of given quantities.

HCF (24, 42, 63) = 3

Maximum capacity of a can = 3 litres

Now, least number of cans required by each milk,

Number of cans of cow milk,

= 24/3

= 8

Number of cans of toned milk,

= 42/3

= 14

Number of cans of double toned milk,

= 63/3

= 21

Then, Total number of cans,

= 3 + 8 + 14

= 25

Hence, the Total number of cans is 25.

Answer 2

Answer:

Given :-

• A milk vendor has 24 litres of cow milk, 42 litres of toned milk and 63 litres of double toned milk if he wants to pack them in cans so that each can contains same litres of milk and does not want to mix any two kinds of milk in a can.

To Find :-

• What is the least number of cans required.

Solution :-

➲ The maximum number of cans we should have to find the maximum capacity cans for required quantity.

First, we have to find the H.C.F of the given quantities :

★ 24 = 2 × 2 × 2 × 3

★ 42 = 2 × 3 × 7

★ 63 = 3 × 3 × 7

➤ HCF of 24 , 42 and 63 :

➦ 3

Hence, the maximum capacity of a can is 3.

Now,

✧ Number of can for cow milk :

↦ 24/3

➠ 8

✧ Number of can for toned milk :

↦ 42/3

➠ 14

✧ Number of can for double toned milk :

↦ 63/3

➠ 21

Now, we have to find the least number of can required :

↦ Total number of can = Can for cow milk + Can for toned milk + Can for double toned milk

↦ Total number of can = 3 + 8 + 14

↦ Total number of can = 11 + 14

➠ Total number of can = 25

∴ The least number of cans required is 25.