A milk vendor has two cans of milk.The first contains 25% water and rest milk.The second contains 50% water.How much mixture should he mix from each of the container so as to get 12 liters of mixture suchc that the rato of mixture is 3:5
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3. A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
A. 5litres, 7 litres
B. 7litres, 4 litres
C. 6litres, 6 litres
D. 4litres, 8 litres
Here is the answer and explanation
Answer : Option C
Explanation :
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Solution 1
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Let x and (12-x) litres of milk be mixed from the first and second container respectively
Amount of milk in x litres of the the first container = .75x
Amount of water in x litres of the the first container = .25x
Amount of milk in (12-x) litres of the the second container = .5(12-x)
Amount of water in (12-x) litres of the the second container = .5(12-x)
Ratio of water to milk = [.25x + .5(12-x)] : [.75x + .5(12-x)] = 3 : 5
⇒
(
.25
x
+
6
−
.5
x
)
(
.75
x
+
6
−
.5
x
)
=
3
5
⇒
(
6
−
.25
x
)
(
.25
x
+
6
)
=
3
5
⇒
30
−
1.25
x
=
.75
x
+
18
⇒
2
x
=
12
⇒
x
=
6
Since x = 6, 12-x = 12-6 = 6