Question

A milkman has 80% milk in his stock of 800 l of adulterated milk . How much 100% pure milk

Answer 1

Answer:

The 100% of quantity of pure milk is 160 liters  .

Step-by-step explanation:

Given as :

Total quantity of milk = 800 liters

The adulated quantity of milk = 80 % of total quantity

i.e The adulated quantity of milk = 80 % × 800 liters

Let The 100% of quantity of pure milk = x liters

∴ The adulated quantity of milk = $\dfrac{80}{100}$ × 800 liters

or, The adulated quantity of milk = 640 liters

Again

The quantity of pure milk = Total quantity of milk - adulated quantity of milk

Or, x = 800 liters - 640 liters

Or , x = 160 liters

So, The 100% of quantity of pure milk = x = 160 liters

Hence, The 100% of quantity of pure milk is 160 liters  . Answer

Answer 2

Question :

A milkman has 80% milk in his stock of 800 liters of adulterated milk. How much 100% pure milk is to be added to it so that purity is between 90% and 95%. How much pure milk should he add to his stock to obtain 99% of pure milk?

To find :

• How much 100% pure milk is to be added to it so that purity is between 90% and 95%.
• How much pure milk should he add to his stock to obtain 99% of pure milk?

Given :

A milkman has 80% milk in his stock of 800 liters of adulterated milk.

Adulterated milk consists of 80% pure milk.

Amount of pure milk in 800 liters = $\frac{80}{100} \times800$ = 640 liters.

Let $x$ liters be the amount of pure milk added to 800 liters of adulteration milk.

The milk content of the mixture form = $\frac{Amount \ of \ pure \ milk \ content}{Total \ volume \ of \ the \ mixture } \times 100$

• Let the amount of pure milk content = $x$ + 640.
• Let the total volume of the mixture = 800 + $x$

$\frac{Amount \ of \ pure \ milk \ content}{Total \ volume \ of \ the \ mixture } \times 100= \frac{x + 640}{800 + x}\times100$

                                                  $=\frac{100x + 64000}{800+x}$

How much 100% pure milk is to be added to it so that purity is between 90% and 95%.

$90<\frac{100 x+64000}{800+x}<95$

$90(800+x)<100 x+64000<95(800+x)$

$72000+90 x<100 x+64000<76000+95 x$

Take the value : $100 x+64000<76000+95 x$

$100 x+64000<76000+95 x$

$5 x<76000-64000$

$5 x<12000$

$x<2400$

Now, take the value : $72000+90 x<100 x+64000$

$72000+90 x<100 x+64000$

$10 x>72000-64000$

$10 x>8000$

$x>800$

Hence,      

$800<x<2400$

How much pure milk should he add to his stock to obtain 99% of pure milk?

If purity is to be made 99%

$\frac{100 x+64000}{800+x}=99$

$100 x+64000=99 x+79200$

$x=79200-64000$

$\boldsymbol{x}=\mathbf{1 5} 2 \mathbf{0} \mathbf{0}$

To learn more...

1. A milkman has one bucket of milk of 80% purity and he has another bucket of milk of 60% purity how much milk of each kind should mix to supply 20 litre of milk of 75% purity​

brainly.in/question/9968771

2.One liter of milk was sold by a milkman which contains 80% pure milk. A housewife adds 200 ml of water to it and drinks 300 ml of the milk. How many liters of pure milk is left after this?

brainly.in/question/1115518