Math, asked by kirangeetha107, 1 month ago


A milkman sells milk at the cost price, but he mixes it with water and thereby gains 15%. The percentage of
water in the mixture is: (assume that water is free) (correct to two decimal places)​

Answers

Answered by rksyadav780gmailcom
0

Step-by-step explanation:

According to the question,

Let's assume milkman has 100 liter of milk, If he added x liter of water, the percentage of water in the mixture=

(100+x)

x

×100

The milk gain 25%, he must have added 25 liter water in 100 liter of milk. Then the percentage of water in the mixture=

(100+25)

25

×100=20%

In the new mixture, If the milk is 80% then 80% of total mixture should be 100 liter

(100+x)×

100

80

=100

8x=200

x=25

Then, the percentage of water in the mixture =

(100+25)

25

×100=20%

Answered by RvChaudharY50
1

Given :- A milkman sells milk at the cost price, but he mixes it with water and thereby gains 15%. The percentage of water in the mixture is : (assume that water is free) (correct to two decimal places) .

Answer :-

Let the milkman bought = 100 litre of milk at Rs.1 / litre .

he sold 100 litre milk at CP = Rs.100 .

but he gains = 15% .

that means

→ Gain = 15% of 100 = Rs.15

so,

→ In order to gain Rs.15 he must sells = 15 litre of water .

therefore,

→ % of water in mixture = (15 * 100) / 115 = 13.04% (Ans.)

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