A milkman sells milk at the cost price, but he mixes it with water and thereby gains 15%. The percentage of
water in the mixture is: (assume that water is free) (correct to two decimal places)
Answers
Step-by-step explanation:
According to the question,
Let's assume milkman has 100 liter of milk, If he added x liter of water, the percentage of water in the mixture=
(100+x)
x
×100
The milk gain 25%, he must have added 25 liter water in 100 liter of milk. Then the percentage of water in the mixture=
(100+25)
25
×100=20%
In the new mixture, If the milk is 80% then 80% of total mixture should be 100 liter
(100+x)×
100
80
=100
8x=200
x=25
Then, the percentage of water in the mixture =
(100+25)
25
×100=20%
Given :- A milkman sells milk at the cost price, but he mixes it with water and thereby gains 15%. The percentage of water in the mixture is : (assume that water is free) (correct to two decimal places) .
Answer :-
Let the milkman bought = 100 litre of milk at Rs.1 / litre .
he sold 100 litre milk at CP = Rs.100 .
but he gains = 15% .
that means
→ Gain = 15% of 100 = Rs.15
so,
→ In order to gain Rs.15 he must sells = 15 litre of water .
therefore,
→ % of water in mixture = (15 * 100) / 115 = 13.04% (Ans.)
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