A milkman sold two of his buffaloes for 20,000 each.
On one he made a gain of 5% and on the other a loss of
10%. Find his overall gain or loss. (Hint: Find
CP of each)
Answers
Answer:
S.P. of each buffalo = Rs.20,000
S.P. of two buffaloes = 20000 x 2
= Rs. 40,000
One buffalo is sold at 5% gain.
Let C.P. be Rs.100, then S.P. = 100 + 5
= Rs.105
\because∵ When S.P. is Rs.105, then C.P. = Rs.100
\therefore∴ When S.P. is Rs.1, then C.P. = \frac{100}{105}105100
\therefore∴ When S.P. is Rs.20,000, then C.P.
= \frac{100}{105}\times20000=Rs.\ 19,047.62105100×20000=Rs. 19,047.62
Another buffalo is sold at 10% loss.
Let C.P. be Rs.100, then S.P. = 100 – 10
= Rs.90
\because∵ When S.P. is Rs.90, then C.P. = Rs.100
\therefore∴ When S.P. is Rs.1, then C.P. = \frac{100}{90}90100
\therefore∴ When S.P. is Rs.20,000, then C.P.
= \frac{100}{90}\times20000=Rs.\ 22,222.2290100×20000=Rs. 22,222.22
Total C.P. = Rs.19,047.62 + Rs.22,222.22
= Rs.41,269.84
Since C.P. >S.P.
Therefore here it is a loss.
Loss = C.P. – S.P.
= Rs.41,269.84 – Rs. 40,000.00 = Rs.1,269.84
Answer:
Solution:
S.P. of each buffalo = Rs.20,000
S.P. of two buffaloes = 20000 x 2
= Rs. 40,000
One buffalo is sold at 5% gain.
Let C.P. be Rs.100, then S.P. = 100 + 5
= Rs.105
\because∵ When S.P. is Rs.105, then C.P. = Rs.100
\therefore∴ When S.P. is Rs.1, then C.P. = \frac{100}{105}
105
100
\therefore∴ When S.P. is Rs.20,000, then C.P.
= \frac{100}{105}\times20000=Rs.\ 19,047.62
105
100
×20000=Rs. 19,047.62
Another buffalo is sold at 10% loss.
Let C.P. be Rs.100, then S.P. = 100 – 10
= Rs.90
\because∵ When S.P. is Rs.90, then C.P. = Rs.100
\therefore∴ When S.P. is Rs.1, then C.P. = \frac{100}{90}
90
100
\therefore∴ When S.P. is Rs.20,000, then C.P.
= \frac{100}{90}\times20000=Rs.\ 22,222.22
90
100
×20000=Rs. 22,222.22
Total C.P. = Rs.19,047.62 + Rs.22,222.22
= Rs.41,269.84
Since C.P. >S.P.
Therefore here it is a loss.
Loss = C.P. – S.P.
= Rs.41,269.84 – Rs. 40,000.00 = Rs.1,269.84
Step-by-step explanation:
pls FREIND MARK ME AS BRAINLIEST
