A milkman sold two of his Buffaloes for rupees 20,000 each.on one he made a gain of 5% and on the other a loss of 10% .Find his overall gain or loss. ( hint: Find CP of each )
Answers
Answer:
1269.84
Step-by-step explanation:SP of each buffalo= 20000
The milkman made a gain of 5% while selling one buffalo.
This means if C.P is 100, then SP is 105
C.P of one buffalo= 20000*100/105= 19047.62
Also, the second buffalo was sold at a loss of 10%
This means if C.P is 100 then SP is 90
C.P of other buffalo = (20000*100/90)= 22222.22
Total C.P = 19047.62+22222.22= 41269.84
Total SP = 20000+20000= 40000
Loss = 41296.64-40000= 1269.84
Thus, THE OVERALL LOSS OF MILKMAN WAS 1269.84
Answer:
Step-by-step explanation:
We will use:
SP = Selling Price; CP = Cost Price
Profit% = P% = 100* (Profit / CP)
Profit = SP - CP
P% = 100 * [(SP - CP) / CP]
= 100 * [(SP/CP) - 1]
On solving for CP, we get:
CP = SP / (1 + (P%/100))
For the first buffalo:
SP = 20000
P% = 5%
CP = 20000/(1 + (5/100))
= 20000/(1 + 0.05)
= 20000/(1.05)
= 19047.62
For the second buffalo:
SP = 20000
P% = -10% (Loss of 10% means profit of -10%)
CP = 20000/(1 - (10/100))
= 20000/(1 - 0.1)
= 20000/(0.9)
= 22222.22
For the combined transaction of two buffaloes:
SP = 20000 + 20000 = 40000
CP = 19047.62 + 22222.22 = 41269.84
As SP < CP, there is a loss
Loss = CP - SP
= 41269.84 - 40000
= 1269.84
Loss% = 100 * (Loss/CP)
= 100 * (1269.84 / 41269.84)
= 3.076
= 3.1% (approx)
Overall, the milkman makes a loss of 3.1%